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(A) In $BF_3$,the boron atom is $sp^2$ hybridized with a bond angle of $120^\circ$. In $BF_4^-$,the boron atom is $sp^3$ hybridized with a bond angle

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$BF_3 + F^- 	o BF_4^-$

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(A) In $BF_3$,the boron atom is $sp^2$ hybridized with a bond angle of $120^\circ$. In $BF_4^-$,the boron atom is $sp^3$ hybridized with a bond angle of $109^\circ 28'$. Thus,this process involves a change in both hybridization and bond angle.In $NH_3$,the nitrogen atom is $sp^3$ hybridized with a bond angle of $107^\circ$. In $NH_4^+$,the nitrogen atom is $sp^3$ hybridized with a bond angle of $109^\circ 28'$. While the bond angle changes,the hybridization remains $sp^3$.In $BF_3 \cdot NH_3$,boron changes from $sp^2$ to $sp^3$ and nitrogen remains $sp^3$ (but its geometry changes from pyramidal to tetrahedral). However,$BF_3 + F^- 	o BF_4^-$ is the most direct example of a change in hybridization from $sp^2$ to $sp^3$ accompanied by a change in bond angle.

Which of the following processes involves a change in bond angle along with a change in hybridization?

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